## Find Sum of a Digit

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**Introduction **

Like, if the user enters 786 then the result is 786=7+8+6=21.

In mathematics, the digit sum of a given integer is the sum of all its digits (e.g.: the digit sum of 84001 is calculated as 8+4+0+0+1 = 13). Digit sums are most often computed using the decimal representation of the given number, but they may be calculated in any other base; different bases give different digit sums, with the digit sums for binary being on average smaller than those for any other base.

**Algorithm:**

**Step 1: START**

Step 2: READ N

Step 3: [INITIALIZE] SUM=0

Step 4: REPEAT STEPS 4 TO 7 WHILE(N!=0)

Step 5: SET REM=N%10

Step 6: SET SUM = SUM+REM

Step 7: SET N=N/10

Step 8: PRINT SUM

Step 9: STOP

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**Program to Find Sum of a Digit:**

#include<stdio.h>

#include<conio.h>

main()

{

int n, rem, sum=0;

printf("\n Enter The Number:");

scanf("%d",&n);

while(n!=0)

{

rem=n%10;

sum=sum+rem;

n=n/10;

}

printf("\n Sum of the value is: %d",sum);

getch();

}

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**Input:**

**We Have To Check the Program using the following input-**

**⦁1st case by giving input as 175**

**⦁2nd case by giving input as 965**

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**Discussion:**

First, we initialized sum=0. We check the digit in a while loop to confirm that if the number is 0 or not, then we store the remainder of n in rem, after that, we store the addition of a reminder and addition in a sum which is previously initialized with 0. Then the number given by the user is divided by 10 and store it in n. After the procedure, we get our expected result.

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